Integrand size = 21, antiderivative size = 122 \[ \int \cot ^6(c+d x) (a+b \sec (c+d x))^2 \, dx=-a^2 x-\frac {a^2 \cot (c+d x)}{d}+\frac {a^2 \cot ^3(c+d x)}{3 d}-\frac {a^2 \cot ^5(c+d x)}{5 d}-\frac {b^2 \cot ^5(c+d x)}{5 d}-\frac {2 a b \csc (c+d x)}{d}+\frac {4 a b \csc ^3(c+d x)}{3 d}-\frac {2 a b \csc ^5(c+d x)}{5 d} \]
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Time = 0.16 (sec) , antiderivative size = 122, normalized size of antiderivative = 1.00, number of steps used = 11, number of rules used = 7, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.333, Rules used = {3971, 3554, 8, 2686, 200, 2687, 30} \[ \int \cot ^6(c+d x) (a+b \sec (c+d x))^2 \, dx=-\frac {a^2 \cot ^5(c+d x)}{5 d}+\frac {a^2 \cot ^3(c+d x)}{3 d}-\frac {a^2 \cot (c+d x)}{d}-a^2 x-\frac {2 a b \csc ^5(c+d x)}{5 d}+\frac {4 a b \csc ^3(c+d x)}{3 d}-\frac {2 a b \csc (c+d x)}{d}-\frac {b^2 \cot ^5(c+d x)}{5 d} \]
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Rule 8
Rule 30
Rule 200
Rule 2686
Rule 2687
Rule 3554
Rule 3971
Rubi steps \begin{align*} \text {integral}& = \int \left (a^2 \cot ^6(c+d x)+2 a b \cot ^5(c+d x) \csc (c+d x)+b^2 \cot ^4(c+d x) \csc ^2(c+d x)\right ) \, dx \\ & = a^2 \int \cot ^6(c+d x) \, dx+(2 a b) \int \cot ^5(c+d x) \csc (c+d x) \, dx+b^2 \int \cot ^4(c+d x) \csc ^2(c+d x) \, dx \\ & = -\frac {a^2 \cot ^5(c+d x)}{5 d}-a^2 \int \cot ^4(c+d x) \, dx-\frac {(2 a b) \text {Subst}\left (\int \left (-1+x^2\right )^2 \, dx,x,\csc (c+d x)\right )}{d}+\frac {b^2 \text {Subst}\left (\int x^4 \, dx,x,-\cot (c+d x)\right )}{d} \\ & = \frac {a^2 \cot ^3(c+d x)}{3 d}-\frac {a^2 \cot ^5(c+d x)}{5 d}-\frac {b^2 \cot ^5(c+d x)}{5 d}+a^2 \int \cot ^2(c+d x) \, dx-\frac {(2 a b) \text {Subst}\left (\int \left (1-2 x^2+x^4\right ) \, dx,x,\csc (c+d x)\right )}{d} \\ & = -\frac {a^2 \cot (c+d x)}{d}+\frac {a^2 \cot ^3(c+d x)}{3 d}-\frac {a^2 \cot ^5(c+d x)}{5 d}-\frac {b^2 \cot ^5(c+d x)}{5 d}-\frac {2 a b \csc (c+d x)}{d}+\frac {4 a b \csc ^3(c+d x)}{3 d}-\frac {2 a b \csc ^5(c+d x)}{5 d}-a^2 \int 1 \, dx \\ & = -a^2 x-\frac {a^2 \cot (c+d x)}{d}+\frac {a^2 \cot ^3(c+d x)}{3 d}-\frac {a^2 \cot ^5(c+d x)}{5 d}-\frac {b^2 \cot ^5(c+d x)}{5 d}-\frac {2 a b \csc (c+d x)}{d}+\frac {4 a b \csc ^3(c+d x)}{3 d}-\frac {2 a b \csc ^5(c+d x)}{5 d} \\ \end{align*}
Result contains higher order function than in optimal. Order 5 vs. order 3 in optimal.
Time = 0.38 (sec) , antiderivative size = 84, normalized size of antiderivative = 0.69 \[ \int \cot ^6(c+d x) (a+b \sec (c+d x))^2 \, dx=-\frac {b \left (3 b \cot ^5(c+d x)+2 a \csc (c+d x) \left (15-10 \csc ^2(c+d x)+3 \csc ^4(c+d x)\right )\right )+3 a^2 \cot ^5(c+d x) \operatorname {Hypergeometric2F1}\left (-\frac {5}{2},1,-\frac {3}{2},-\tan ^2(c+d x)\right )}{15 d} \]
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Time = 2.06 (sec) , antiderivative size = 154, normalized size of antiderivative = 1.26
method | result | size |
derivativedivides | \(\frac {a^{2} \left (-\frac {\cot \left (d x +c \right )^{5}}{5}+\frac {\cot \left (d x +c \right )^{3}}{3}-\cot \left (d x +c \right )-d x -c \right )+2 a b \left (-\frac {\cos \left (d x +c \right )^{6}}{5 \sin \left (d x +c \right )^{5}}+\frac {\cos \left (d x +c \right )^{6}}{15 \sin \left (d x +c \right )^{3}}-\frac {\cos \left (d x +c \right )^{6}}{5 \sin \left (d x +c \right )}-\frac {\left (\frac {8}{3}+\cos \left (d x +c \right )^{4}+\frac {4 \cos \left (d x +c \right )^{2}}{3}\right ) \sin \left (d x +c \right )}{5}\right )-\frac {b^{2} \cos \left (d x +c \right )^{5}}{5 \sin \left (d x +c \right )^{5}}}{d}\) | \(154\) |
default | \(\frac {a^{2} \left (-\frac {\cot \left (d x +c \right )^{5}}{5}+\frac {\cot \left (d x +c \right )^{3}}{3}-\cot \left (d x +c \right )-d x -c \right )+2 a b \left (-\frac {\cos \left (d x +c \right )^{6}}{5 \sin \left (d x +c \right )^{5}}+\frac {\cos \left (d x +c \right )^{6}}{15 \sin \left (d x +c \right )^{3}}-\frac {\cos \left (d x +c \right )^{6}}{5 \sin \left (d x +c \right )}-\frac {\left (\frac {8}{3}+\cos \left (d x +c \right )^{4}+\frac {4 \cos \left (d x +c \right )^{2}}{3}\right ) \sin \left (d x +c \right )}{5}\right )-\frac {b^{2} \cos \left (d x +c \right )^{5}}{5 \sin \left (d x +c \right )^{5}}}{d}\) | \(154\) |
risch | \(-a^{2} x -\frac {2 i \left (30 a b \,{\mathrm e}^{9 i \left (d x +c \right )}+45 a^{2} {\mathrm e}^{8 i \left (d x +c \right )}+15 b^{2} {\mathrm e}^{8 i \left (d x +c \right )}-40 a b \,{\mathrm e}^{7 i \left (d x +c \right )}-90 a^{2} {\mathrm e}^{6 i \left (d x +c \right )}+116 a b \,{\mathrm e}^{5 i \left (d x +c \right )}+140 a^{2} {\mathrm e}^{4 i \left (d x +c \right )}+30 b^{2} {\mathrm e}^{4 i \left (d x +c \right )}-40 a b \,{\mathrm e}^{3 i \left (d x +c \right )}-70 a^{2} {\mathrm e}^{2 i \left (d x +c \right )}+30 a b \,{\mathrm e}^{i \left (d x +c \right )}+23 a^{2}+3 b^{2}\right )}{15 d \left ({\mathrm e}^{2 i \left (d x +c \right )}-1\right )^{5}}\) | \(187\) |
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Time = 0.27 (sec) , antiderivative size = 152, normalized size of antiderivative = 1.25 \[ \int \cot ^6(c+d x) (a+b \sec (c+d x))^2 \, dx=-\frac {30 \, a b \cos \left (d x + c\right )^{4} + {\left (23 \, a^{2} + 3 \, b^{2}\right )} \cos \left (d x + c\right )^{5} - 35 \, a^{2} \cos \left (d x + c\right )^{3} - 40 \, a b \cos \left (d x + c\right )^{2} + 15 \, a^{2} \cos \left (d x + c\right ) + 16 \, a b + 15 \, {\left (a^{2} d x \cos \left (d x + c\right )^{4} - 2 \, a^{2} d x \cos \left (d x + c\right )^{2} + a^{2} d x\right )} \sin \left (d x + c\right )}{15 \, {\left (d \cos \left (d x + c\right )^{4} - 2 \, d \cos \left (d x + c\right )^{2} + d\right )} \sin \left (d x + c\right )} \]
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\[ \int \cot ^6(c+d x) (a+b \sec (c+d x))^2 \, dx=\int \left (a + b \sec {\left (c + d x \right )}\right )^{2} \cot ^{6}{\left (c + d x \right )}\, dx \]
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Time = 0.28 (sec) , antiderivative size = 96, normalized size of antiderivative = 0.79 \[ \int \cot ^6(c+d x) (a+b \sec (c+d x))^2 \, dx=-\frac {{\left (15 \, d x + 15 \, c + \frac {15 \, \tan \left (d x + c\right )^{4} - 5 \, \tan \left (d x + c\right )^{2} + 3}{\tan \left (d x + c\right )^{5}}\right )} a^{2} + \frac {2 \, {\left (15 \, \sin \left (d x + c\right )^{4} - 10 \, \sin \left (d x + c\right )^{2} + 3\right )} a b}{\sin \left (d x + c\right )^{5}} + \frac {3 \, b^{2}}{\tan \left (d x + c\right )^{5}}}{15 \, d} \]
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Leaf count of result is larger than twice the leaf count of optimal. 273 vs. \(2 (112) = 224\).
Time = 0.36 (sec) , antiderivative size = 273, normalized size of antiderivative = 2.24 \[ \int \cot ^6(c+d x) (a+b \sec (c+d x))^2 \, dx=\frac {3 \, a^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} - 6 \, a b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} + 3 \, b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} - 35 \, a^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} + 50 \, a b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} - 15 \, b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} - 480 \, {\left (d x + c\right )} a^{2} + 330 \, a^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - 300 \, a b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 30 \, b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - \frac {330 \, a^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{4} + 300 \, a b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{4} + 30 \, b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{4} - 35 \, a^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} - 50 \, a b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} - 15 \, b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} + 3 \, a^{2} + 6 \, a b + 3 \, b^{2}}{\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5}}}{480 \, d} \]
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Time = 13.70 (sec) , antiderivative size = 191, normalized size of antiderivative = 1.57 \[ \int \cot ^6(c+d x) (a+b \sec (c+d x))^2 \, dx=\frac {{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^5\,{\left (a-b\right )}^2}{160\,d}-a^2\,x-\frac {{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^3\,\left (\frac {a^2}{16}-\frac {a\,b}{12}+\frac {b^2}{48}+\frac {{\left (a-b\right )}^2}{96}\right )}{d}-\frac {\frac {2\,a\,b}{5}+{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^4\,\left (22\,a^2+20\,a\,b+2\,b^2\right )+\frac {a^2}{5}+\frac {b^2}{5}-{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2\,\left (\frac {7\,a^2}{3}+\frac {10\,a\,b}{3}+b^2\right )}{32\,d\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^5}+\frac {\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )\,\left (\frac {21\,a^2}{32}-\frac {9\,a\,b}{16}+\frac {b^2}{32}+\frac {{\left (a-b\right )}^2}{32}\right )}{d} \]
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